Question

p(x)/x+1=(2x^2-3x+1) + -2/x+1, find p(x)

Answer 1

multiply both sides by (x+1)

Answer 2

See what that gets you

Answer 3

\[\frac{ P(x) }{ x+1 }= (2x^2-3x+1)+ (\frac{ -2 }{ x+1 })\]

Find the common denominator of the second side.

\[\frac{ P(x) }{ x+1 }=\frac{ (x+1)(2x^2 -3x+1)-2}{ x+1}\]

and now x+1 can just cancel out and you are left with p(x)= (x+1)(2x^2-3x+1)-2

Answer 4

thanks