Question

solve abs(tanx)=1 ?
would it be tan(x)=1 tan(x)=-1
and then the pi values?

Answer 1

It is like solving tan^2(x)=1
which give the two equations tan(x)=1 or tan(x)=-1

Answer 2

And yeah |f(x)|=f(x) or -f(x)
depending our values of x in which f is positive or negative

Answer 3

there is no interval asked in the question so would it be like x = 3pi/4 +-pik?

Answer 4

Well that is one equation...there should be another

Answer 5

wait that should be fine

Answer 6

yeah the one for tanx = 1

Answer 7

and for tanx = 1

Answer 8

i meant -1

Answer 9

yeah we need the one for tan(x)=1 also

Answer 10

then i think i got it thank you :D

Answer 11

I would have said x=pi/4+npi , -pi/4+npi

Answer 12

well i got 3pi/4 +-pik and pi/4+-pik

Answer 13

same thing

Answer 14

my presents any integers
(not just positive)
you don't need +/- unless you want your k's to be nonnegative integers

Answer 15

I was talking about my n represents any integer*

Answer 16

:O i didnt know that

Answer 17

ty

Answer 18

But you can leave it that way
It is fine