Question

average salary for total employees is 2000.If the grade A employees's average salary is 4000, and grade B employee's average salary is 1250 then the total numbers of employees could be

Answer 1

a. 450
b. 300
c. 110
d. 500

Answer 2

suppose there are \(\large n\) total employees and out of which \(\large a\) employees are of grade \(\large a\) :
\[\large 1250a + 4000(n-a) = 2000n\]

Answer 3

can you simplify that equation further ?

Answer 4

simplify it till the point you get this :
\[\large 8n = 11a\]

Answer 5

since 11 is a prime and cannot divide 8, that means \(\large 11\) must divide \(\large n\)

Look at your options - which option is a multiple of 11 ?

Answer 6

its c

Answer 7

Yep!

Answer 8

can i use digit sum trick here

Answer 9

you can.. all those tricks you had memorized are useful in working these problems quick

Answer 10

i found the ration 8a=3b

Answer 11

work it again

Answer 12

*ratio

Answer 13

but we're working a, n right ?

Answer 14

who is this b ?

Answer 15

b grade employees

Answer 16

why are u working b grade employees ?
the equation we setup involves only a and n eh ?

Answer 17

ok

Answer 18

thanks very much

Answer 19

np :) you can simply replace a by n-b in ur equation :

8a = 3b

Answer 20

8(n-b) = 3b

8n = 11b

Answer 21

we get the same result again - n needs to be a multiple of 11

Answer 22

yes ur method makes sense