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Linear Algebra
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2y+3=-1/3(x-2) in standard form
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include steps
Standard form is y=mx+b First simplify the equation: 2y+3= -1/3(x-2)
So combine like terms: 2y+3 = -1/3x +2/3 2y=-1/3x-7/3 To get rid of fractions, multiply by 3: 6y = -x - 7
then divide it all by 6: y=-1/6x-7/6
you do realize standard form is ax+by=c that is slope-intercept form you did
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Oh shoot, yea i forgot.. I'm old lol. Hang on, gimme a chance
ok
2y+3= -1/3(x-2) ax+by=c 2y+3=-1/3x+2/3 2y+1/3x=-7/3 To get rid of fractions, multiply by 3: 6y+x=-7
or... x+6y = -7
thxxxxx
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