Consider the exponential function y=b^x, b>0. Determine the value for b for which the graph of y=b^x intersects the line y=x.
y = b^x y = x If the graphs intersect then b^x = x Solve for x.
I meant solve for b.
The only way I can see how to solve for b such that b^x=x is to do it just by guessing... There is one value b such that b^x=x from what I can tell.
And I mean there is one value b such that b^x=x for some real value x
what does it mean that it must intersect the line y=x?
that one curve must go through the other curve is what intersects means
you have heard of intersections in highways
|dw:1413424680111:dw| look at that exponential equation it doesn't touch the y=x line
There should be a b that you can think of so that y=b^x is not an exponential equation
It will if 0 < b < 1
exponential decay function instead of a growth function.
|dw:1413425000218:dw|
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