Question

In this question you will derive a general formula for the distance of a point from a line. Let P be the point (p,q) and L the line y=mx+b.
The slope of L is m

The slope of a line perpendicular to L is -1/m

The line through P perpendicular to L can be written as y=sx+c
where s is: -1/m
and c is: q+(p/m)
That line intersects L in the point Q=(u,v),

where u is: __________
and v is: ____________

The distance of P and Q is ________

Answer 1

solve below equations for x and y :

y = mx + b
y = sx + c

Answer 2

can you ?

Answer 3

y = mx+sx+b+c ? @ganeshie8

Answer 4

over 2 sorry so y = (mx+sx+b+c )/2