Question

solve using elimation or substitution, which ever.

x + 2y = 8
3x + 6y = 12

Answer 1

\[x+2y=8\]
\[2y=8-x\]
\[y=4-\frac{1}{2}x\]

Answer 2

\[3x+6(4-\frac{1}{2}x)=12\] you need to solve for x here and plug it into the first equation to find y

Answer 3

Not a good plan.

x + 2y = 8
3x + 6y = 12

Multiply the top by 3

3x + 6y = 24
3x + 6y = 12

This system is going nowhere. No solution.

Answer 4

The solution set is $$\emptyset$$

Answer 5

thank you all

Answer 6

Thanks for asking :-)