How to get a focal point and parabolic curve out of the equation: y = (x + 1)^2?

Question

tkhunny · Answer

First, find the vertex.

anonymous · Answer

Right and you can tell the shape of the graph from the equation given

anonymous · Answer

Find Vertex by expanding out your equation and finding your A, b and c.  And use the axis of symmetry -b/2a

anonymous · Answer

this will give you your x value for vertex you find y by putting it into the equation as a Function of x

tkhunny · Answer

Normally, the Vertex Form is like this:

4p(y-k) = (x-h)^2

You have:

k = 0,
h = -1, and
4p = 1 or p = 1/4

The vertex is (-1,0).

Use 'p' to find both Directrix and Focus.

firejay5 · Answer

thank you so much @tkhunny  and @Emily.lynn97

anonymous · Answer

No problem, I usually find the axis of symmetry way a little easier to find vertex if you are horrible at factoring like me lol