Question

Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (-6, 3).

y = three halvesx - 1

y = three halvesx + 3
@gorv

Answer 1

y=3x/4+4

Answer 2

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6

y = -one thirdx - 14

y = 3x - 6

y = 3x - 14

Answer 3

oops sorry, meant that one.

Answer 4

product of slope of perpendicular lines=-1
let slope of perpendicular line =m

Answer 5

convert it in standard form
y=mx+c

Answer 6

add 3 on both side
wat u got ??

Answer 7

3x & 0.

Answer 8

3x-y=0

Answer 9

nope u have to add on both side

Answer 10

3x-y+3=0 this will we get

Answer 11

now add y on both side

Answer 12

I just got so confused lol.

Answer 13

Running out of time on the test too.. :/

Answer 14

3x+3=y
slope =3

Answer 15

y=3x+c equation of parallel line

Answer 16

itzz passing through (4,-2)
-2=3*4+c
-2=12+c
c=-14

Answer 17

y=3x-14

Answer 18

Okay, thank you. :)

Answer 19

welcome