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Mathematics 16 Online
OpenStudy (anonymous):

http://media.education2020.com/evresources/2090767_4c9f7c49-0105-482a-ab43-4a5a202db1a9.png Find http://media.education2020.com/evresources/2004-04-01-05-00_files/i0400000.jpg

OpenStudy (anonymous):

idk this one

ganeshie8 (ganeshie8):

\(\large \angle QSR = 180 - 150 = 30\) \(\large \tan (\angle QSR ) = \tan(30) = ?\)

OpenStudy (anonymous):

The angle of S must be 30 degrees (180-150), and since R is a right angle, Q is 60 degrees (180 - (90+30)). This is a 30-60-90 triangle, so tan(ang[QSR]) is equal to the one divided by the square root of 3 (1 / sqrt(3)).

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