Question

Solve the system by substitution:
14x-35=7y
-25-6x=5y
I just need someone to walk me through this I really have no idea how to go about doing it...

Answer 1

You have two unknowns and two equations. Solve for either x or y using one of them; here, let's solve for y using the first one.
14x - 35 = 7y --> y = 2x - 5

Now substitute (2x - 5) for y, since they are equivalent, and solve for x.
-25 - 6x = 5(2x - 5)--> -25 - 6x = 10x - 25 --> 16x = 0 --> x = 0

You will have to solve for y now.
y = 2(0) - 5 = 0 - 5 = -5

Now check the validity of (x, y) = (0, -5).
14(0) - 35 = 7(-5) --> -35 = -35 | TRUE
-25 - 6(0) = 5(-5) --> -25 = -25 | TRUE

x = 0, y = -5

Answer 2

Oh my goodness thank you so much!!