MEDAL AND FAN!!!!!
@campbell_st @MIA305DT
@ManImStumped please help me!!
@Kainui please help me :'((
I would look at the green curve first...and then look at the other curves and see if they are f' and f'' if that is f
Notice it is increasing until we get to 1.5 then there sorta like a vertical line almost there the slopes after that should appear to you like the slopes are getting closer to 0 then after than again it looks like we kinda sorta have a vertical line again at 4.7 maybe... But that is decreasing and decreasing after the vertical-ish part... I hope this is a hint on how you should determine f'... And then you can determine f'' from f'
@freckles ohh so it would be D right?
@perl @amistre64
@e.mccormick HELP
@MIA305DT
how would you define the relationship between f f' and f"
uhh
what is your concept of derivatives is all
youre asking me what derivatives are?
yeah, fundamentally what are they?
a slope of a curve or a rate of change
yeah and the graphs are really not that easy to descern for me but, we are more interested in +,- and 0 for f' instead of the actual values
notice A, it looks to be curving upwards at the left, so its derivative would have to be + and moving until it changes direction
okk
when A changes about and starts heading down, we need a - value to me, it looks like C is defining the slope of A C = A' to me
ok gotcha so far
can we narrow the options? when that has A to C?
wait so it is not D?
it could be D according to the A then C setup but i cant place B in front of A at the moment
its trying to match curves thats a pain :) A and C are related, and it looks to me that A can define the slope of C as well C to A seems a good option to me now that i stare at it more lol
it B that just doesnt really fit the bill for anything to me, so im most prone to pick the first option :)
B moves its slope as +++++ undefined+++++++0--------- B moves how C is defined
you think that the answer cannot be determined?
but A does not move how B is defined B = ------0++++++++++++0---------- A = ++++undefined++++++++0------
i cant see a solution that satisfies it. if we try to back solve it ... test out if the options make sense
okk
@jim_thompson5910
AB is not a good fit CA is good, is AB? no, we already determined that AB is bad BA is bad ... so those 3 options just dont work for me
The only reason I told you to start with green curve is because it would no sense otherwise to me that is. Green was continuous but not differentiable at those two particular spots I talked about so you will have va there for the derivative. We cannot start with a non-continuous function (well at those two points) and take derivative and somehow get a continuous function (at those two points)
Both of the other two curves were non-continuous at those points.
its all about trial and error to me :)
it looks like they don't have the right choice listed
So i guess it would have to be A(:
assume an option is right, and show that its wrong ... in the end, the only one left standing has to be the solution
well the answer can be determined it is just not listed
6 possibilities? any of them make sense?
abc acb bca bac cab cba i dont think any of them fit well enough
do you know which is the right combination i was going to put it but i took away
I want you to tell me @mondona
and it doesn't have to be a choice listed
ab and ba are simply not doable permutes acb bca these are the only possible ones, and i havent tried them
but those are my only choices lol
I disagree with your possible choices
The question itself was messed up anyways
it said f , f' and f'
not f, f', and f''
the double tick was line feed
question messed up so so could answers be
oh on next line
i'm a goofy
so my possible answers are right?! hahahha
Well I still say they are wrong
I have the choice in my head and I badly want to tell you because answer isn't listed
But I want you to say it first.
nevermind guys, just drop it lol im putting A
cb is bad that leaves bca which i cant see anything particulalriy wrong with
bca !!! all the way
I guess you have to put a choice don't you mondona? Like this online homework?
good luck all the same ;)
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