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@phi
i got 1
I think you should think about the left and right derivative as x->3 of that absolute value part
okk
JK ITS 0 THANKS
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|x|=x if x>0 |x|=-x if x<0 |x|=0 if x=0 therefore there is a sharp derivative at x=0 of the function f(x)=|x| so actually the derivative of |x| is 1 if x>0 -1 if x<0 dne if x=0
So think about |3x-9|
at x=3
Think about graph if you have too
Is there a sharp turn?
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When you write it as a piece function do the slopes match up on both sides at x=3
an absolute value function makes a sharp "V" at the vertex, the sudden change in direction makes the slope at that point undefined. in other words, you should not expect a value for the derivative of your function at x=3
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