Question

write y=2x^2+2 in vertex form

Answer 1

have you covered quadratics or 2nd degree equations yet?

Answer 2

\[y=2*(x-0)^{2} + 2 \]
is that right?

Answer 3

\[h=\frac{ -b }{ 2a }\]

Answer 4

\[k=\frac{ -\Delta }{ 4a }\]
then you do\[y=(a-h)^{2} + k\]
\[ax^{2} +bx + c = 0\]
you make the substitution and you get what you want