Question

somebody please help me. thank you sooo much!!

Answer 1

i totally forgot where i got these numbers:

Answer 2

well for this problem the first on a.

Answer 3

sorry actually the second on b.
this is my work but i totally forgot were i got those exponents

Answer 4

sorry it is slanted! i can fix it if you need thanks

Answer 5

i don't understand were the exponents 3 and 2 and how i got those

Answer 6

so I am not exactly clear on what you are asking, but I believe you are doing something with binomial expansion, sound familiar?

Answer 7

3 and (5-3)
for a sum of 3+(5-3)=5
that 3 there is for the 3rd term

Answer 8

5 is what your thing binomial was to the power of

Answer 9

\(\large r\)th term in binomial exansion \(\large (a+b)^n\) :

\[\large \binom{n}{r-1}a^{n-(r-1)}b^{r-1}\]

Answer 10

yes @myininaya but for this problem:

Answer 11

oh that problem is for 2c

Answer 12

but i don't understand if the 2 is for the 2nd term then why isn't the 2^2 but 2^3?

Answer 13

First of all, your first term in binomial \(\large (2a+b)\) is not just \(\large 2\),
it is \(\large 2a \)

Answer 14

oh yes sorry

Answer 15

next, use the \(\large r\)th term formula

Answer 16

I should have said 5-(3-1) and (3-1) by the way...
for the sum of 5 and
since 3 was the 3rd term

Answer 17

\(\large 2\)nd term in binomial exansion \(\large (2a+b)^4\) :

\[\large \binom{4}{2-1}(2a)^{4-(2-1)}b^{2-1}\]

Answer 18

wait thou idk if you can see 2d. but i don't understand how the exponent 5 is with 4 and not with the 3
thank you ganeshie

Answer 19

np :) is there a question still ?

Answer 20

no i don't believe so thank youuu all! :D

Answer 21

yw, it could be confusing with those too many exponents and subtraction signs, they are unnecessary.. i memorize only the binomial expansion formula and deduce nth term when required :
\[\large (a+b)^n = \sum\limits_{r=0}^n\binom{n}{r}a^{n-r}b^r\]

you memorize which ever is easy for you :)
`

Answer 22

yayay! thanks again