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Mathematics 9 Online
OpenStudy (anonymous):

This was just an odd question to me. each different letter of the word "average" is written on a card and placed in a hat. One card is drawn from the hat. How many possible outcomes are there for this experiment?

OpenStudy (anonymous):

so you have to take all the letters from the hat?

OpenStudy (anonymous):

so 7 would be all letters

OpenStudy (anonymous):

each DIFFERENT letter, so only a-v-e-r-g, no?

OpenStudy (anonymous):

5 different outcomes I mean

OpenStudy (anonymous):

Let me retype that

OpenStudy (anonymous):

ok i get u now

OpenStudy (anonymous):

I think what they mean is that there are 5 letters written in 5 cards. I said 5 because the letter a is repeated twice and they want different letters. This means that there are 5 possible outcomes, and if one card is drawn out, 1/5.

OpenStudy (anonymous):

Also e is repeated.

OpenStudy (anonymous):

if you have take all 5 letters and you want to know the number of possible permutations (orders), you do it like this: 5! (5*4*3*2*1) which is 120

OpenStudy (anonymous):

I'm pretty sure I understand this now... like what about the word percent like in the same type of question i just asked wouldn't that be 5 too

OpenStudy (anonymous):

or 6

OpenStudy (anonymous):

'percnt'

OpenStudy (anonymous):

Yeah 6

OpenStudy (anonymous):

You might want to do what Fallontine did though.

OpenStudy (anonymous):

There would only be five cards placed into the hat because the letter "e and a" repeat. 1/5= 20%

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