This was just an odd question to me. each different letter of the word "average" is written on a card and placed in a hat. One card is drawn from the hat. How many possible outcomes are there for this experiment?
so you have to take all the letters from the hat?
so 7 would be all letters
each DIFFERENT letter, so only a-v-e-r-g, no?
5 different outcomes I mean
Let me retype that
ok i get u now
I think what they mean is that there are 5 letters written in 5 cards. I said 5 because the letter a is repeated twice and they want different letters. This means that there are 5 possible outcomes, and if one card is drawn out, 1/5.
Also e is repeated.
if you have take all 5 letters and you want to know the number of possible permutations (orders), you do it like this: 5! (5*4*3*2*1) which is 120
I'm pretty sure I understand this now... like what about the word percent like in the same type of question i just asked wouldn't that be 5 too
or 6
'percnt'
Yeah 6
You might want to do what Fallontine did though.
There would only be five cards placed into the hat because the letter "e and a" repeat. 1/5= 20%
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