Question

what is the value of n so that the expression x^2+12+n is a perfect square trinomial?
6
36
72
144

Answer 1

n=(12/2)^2

Answer 2

so then consider that there need being

x^2 +12 +n so this rewrite it like x^2 +2*6 +n so for a perfect square n need being a square of 6 so this mean that n=36

hope this will help you