Question

Could someone see if I did this right?

Answer 1

Find the surface area of the solid formed by the net.

Answer 2

I got: 25.13 in^2

Answer 3

what did you use to find the width of the rectangle?

Answer 4

I didn't find the width. I used these two formulas:
\[\Pi \times r ^{2}\]
\[2 \times \pi \times r \times h\]

Answer 5

but you were spose to use the net :)

2 circles and a rectangle

pi(1)^2 + pi(1)^2 + 3(C)

C is the width of the rectangle, and is equal to the circumference of one of the xircles

Answer 6

C = 2pi soo the total area is 8pi which is about 25.xxx

Answer 7

i just noticed something lol

the formula IS the net

pi r^2 + pi r^2 + 2pirh

but i suspect that you werent spose to play that way is all and they wanted yo to determine that on your own

Answer 8

So, I am correct? @amistre64