Question

how do you find the sides of a triangle that is 30-30-120 if the perimeter equals 18?

Answer 1

hi sorry for not responding to the other so can you draw a picture of this triangle?

Answer 2

So we have P = 18 = \(2h+2h+2\sqrt3 h=(4+2\sqrt{3})h\), right?

So we can divide both sides by \(4+2\sqrt{3} \), get ourselves \(h=\dfrac{18}{4+2\sqrt3}\approx2.412\)

So for sides, we have \(2h\), \(2h\), and \(2\sqrt3 h\)

With \(h\approx2.412\), we have sides length of 4.823, 4.823, 8.354 respectively.