how do you find the sides of a triangle that is 30-30-120 if the perimeter equals 18?

Question

anonymous · Answer

hi sorry for not responding to the other so can you draw a picture of this triangle?

anonymous · Answer

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geerky42 · Answer

|dw:1413607237309:dw||dw:1413607267461:dw|So we have P = 18 = $2h+2h+2\sqrt3 h=(4+2\sqrt{3})h$, right?

So we can divide both sides by $4+2\sqrt{3} $, get ourselves $h=\dfrac{18}{4+2\sqrt3}\approx2.412$

So for sides, we have $2h$, $2h$, and $2\sqrt3 h$

With $h\approx2.412$, we have sides length of 4.823, 4.823, 8.354 respectively.

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