Question

1- y*lnx*lny*dx+x*dy=0

Answer 1

are these exact equations?

Answer 2

yes

Answer 3

then how much do you know about finding a solution

Answer 4

this is equations .. how i can solution?

Answer 5

the general process is to integrate one side, add on a function, and derive to the other side to compare with

Answer 6

given:

M(x,y) dx + N(x,y) dy = 0

integrate one side int: M(x,y) dx

add a function: int: M(x,y) dx + f(y)

and take the derivaitve

d/dy [int: M(x,y) dx + f(y)] = N(x,y) dy

Answer 7

y*lnx*lny*dx+x*dy = 0

since xdy is simple enough .... integrate to get xy

add a function of x to it: xy+ f(x) and take the derivative, equate it to the other side

[xy+ f(x)]' = y + xy' + f'(x) = y*lnx*lny*dx

maybe the other direction?

Answer 8

i got no good way past that .... see if you can glean something from the wolfs

http://www.wolframalpha.com/input/?i=y*lnx*lny*dx%2Bx*dy+%3D+0

Answer 9

Thank you very much

Answer 10

yep, good luck :)