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Mathematics 7 Online
OpenStudy (anonymous):

cube root of 2x/9y

TheSmartOne (thesmartone):

\[\sqrt[3]{\frac{ 2x }{ 9y }}\]

OpenStudy (anonymous):

yes please...

TheSmartOne (thesmartone):

=\[(\frac{ 2x }{9y })^{\frac{1}3}\]

TheSmartOne (thesmartone):

You can't simplify it...

TheSmartOne (thesmartone):

@Vsanchez653

OpenStudy (anonymous):

i need a problem to work off of... If this problem cant be simplifyed then can this promble be simplifyed? --- 4th root of 2/3x^2

TheSmartOne (thesmartone):

no...

TheSmartOne (thesmartone):

Do you want me to give you an example of one that can be simplifed...

TheSmartOne (thesmartone):

@Vsanchez653

OpenStudy (anonymous):

okay

TheSmartOne (thesmartone):

\[\sqrt[4]{625x^4}=(625x^4)^{1/4}=(5^4)^{1/4}(x^4)^{1/4}=5x\]

TheSmartOne (thesmartone):

Does that help you @Vsanchez653

OpenStudy (anonymous):

yes it does.. Thank you..but im still curious about 4th root of 2x/3x^2

TheSmartOne (thesmartone):

That would equal to \[\frac{ \sqrt[4]{2x} }{ \sqrt[4]{3x^2} }=\frac{ \sqrt[4]{2x} }{ \sqrt[4]{3}\times \sqrt{x} }\]

TheSmartOne (thesmartone):

That is the max you can simplify it...

TheSmartOne (thesmartone):

Here are some formulas that might help you \[(ab)^m=a^m \times b^m\] \[(a^m)^n=a^{m \times n}\] \[a^m \times a^n=a^{m+n}\] \[\frac{ a^m }{ a^n }=a^{m-n}\] \[\sqrt[n]{x}=x^{\frac{ 1 }{ n }}\] \[\sqrt[n]{xy}=\sqrt[n]{x}\times \sqrt[n]{y}\]

TheSmartOne (thesmartone):

@Vsanchez653

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