Question

Convergent of divergent

Answer 1

\[\sum_{n=1}^{\infty} \frac{ n! }{ n^n }\]

@ganeshie8

Answer 2

Is it possible to use limit comparison test here?

Answer 3

Already wrong

Answer 4

convergent

Answer 5

Try using the ratio test

Answer 6

I don't think the limit test will suffice here.

Answer 7

Yeah, mhm let me try that

Answer 8

Ratio test will work but it will be tedious :d

Answer 9

it has to be convergent

Answer 10

\[a_n=\frac{ n! }{ n^n }~~~~a_{n+1} = \frac{ n!(n+1) }{ (n+1)^{n+1} }\]