Question

y1 -3/y^2 = 3/x^2 would be y1 = -y^2/x^2 ?

Answer 1

can't wait to see this answer ...

Answer 2

\[y' \cdot \frac{-3}{y^2}=\frac{3}{x^2} ?\]
and you are solving for y'?

Answer 3

multiply both sides by the reciprocal of what is next to the y'

Answer 4

and yes

Answer 5

He was doing derivative junk earlier so I think he meant y' instead of y1

Answer 6

yes

Answer 7

and I think he was doing the question find y' given 1/x+1/y=1

Answer 8

ok thanks just making sure