factorise x^2-4x-21
Use the product and sum method to factor quadratics. Find two number that multiply to get -21 and add to get -4
or you can simple use \[x _{1,2}=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
Source http://www.mathsisfun.com/algebra/polynomials-sums-products-roots.html
Yes, you can use the quadratic formula, but sometimes it is too tedious, so a faster approach would the product and sum method.
(x-7) (x+3)
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\(\Large \begin{align} \color{black}{\text{u can also use squaring method}\\ x^2-4x-21\\ =x^2-4x+4-4-21\\ =(x-2)^2-25\\ =(x-2)^2-(5)^2\\ =(x-2+5)(x-2-5)\\ =(x+3)(x-7)}\end{align}\)
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