Please help me with a question that involves derivatives! I thought I was doing the problem was correctly, but the answers in the textbook is different
i don't understand what's happening in your third line you want the derivative of \(x^2\sin x\) at x=3 ?
or is this a linear approximation?
Yeah.
I thought I got the derivative properly.
yes, line 2 is correct I don't quite understand what you want though, do you want the equation for the tangent line at x=3 or what?
I need to find out the tangent line at x=3.
Can you see where I went wrong? In the previous question I asked, someone said to use the formula y=(derivative of f(a))*(x-a)+(f(a))
In this problem its not working though and I don't know why.
well for one thing you wrote 9cos3 when plugging in x-3 for x^2-cosx should give 9-cos3
x=3*
i think that's the only error
Okay. but why should it be 9-cos3?
oh i misread your writing
what is the answer supposed to be?
cause it looks right but i haven't busted out the calculator
The answer is supposed to be (9cos3 + 6sin3)x - 27cos3 -9sin3 They say the decimal approximation is y=-8.063x+25.460
and how is that not what you have? your expression simplifies to (9cos3 + 6sin3)x - 27cos3 -9sin3 it must e a calculator error perhaps radian/degree issue
yep checks out in radians just fine
OHHHHH!!!!! Omg it was a silly mistake I was making!! I'm sorry for spending so much time on this problem!!
haha it happens to the best of us. and me
Thanks so much for helping me! I'm sorry!!
no worries! you'll only make that mistake 100 more times before you get past it, just part of the process ;)
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