Question

Find all values of t in the interval [0, 2pi] that satisfy the given equation: sin t=square root 2/2

Answer 1

so then

\[x = \sin^{-1}(\frac{2\sqrt{2}}{2}) = \frac{\pi}{4}\]

so you have the 1st quadrant angle, you just need to find the 2nd quadrant angle

which requires

\[\pi - x\]