What is the slope-intercept form of the function that contains the points (6, 2) and (4, 8)?
As a start : find the slope from given points
@ganeshie8 I found the slope and its like this.
yes, whats the slope ?
use the slope formula http://www.algebra-class.com/image-files/slope-formula-2.gif
(6, 2) and (4, 8) x1 y1 x2 y2
slope = (y2 - y1)/(x2 - x1) = (8 - 2)/(4 - 6) = ?
Ahh, (2,-6) right?
2/-6.
slope is a single number...
slope = (y2 - y1)/(x2 - x1) = (8 - 2)/(4 - 6) = 6/-2 = -3
slope = -3
Yeah, but what about this? y = ? x + ? fill in the ?
Its from this question.
slope intercept form of line is : \[\large y = \color{Red}{m}x + \color{Red}{b}\]
\(\large \color{red}{m}\) : slope \(\large \color{red}{b}\) : y intercept
you know slope already, right ?
Yes?
you just need to find the y intercept
\[\large y = \color{Red}{-3}x + \color{Red}{b}\]
plugin any of the given points into above equation and solve `b`
maybe plugin the first point (6, 2) : \[\large 2 = \color{Red}{-3}(6) + \color{Red}{b}\] solve `b`
Well, i just dont understand what is b.
you need to solve the above equation for `b`
\[\large 2 = \color{Red}{-3}(6) + \color{Red}{b}\] \[\large 2 = -18 + \color{Red}{b}\] \[\large 20 = \color{Red}{b}\]
I still got more anyone care to look?
everyone here is for helping only, however you need to try a bit and ask only the part that doesn't make sense..
i have noticed that you're stuck at solving `2 = -3(6) + b` haven't you dealt with solving equations like that before ?
No not really.
I see... they are called `two step equations` see this for mastering them https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-variables-expressions/cc-7th-2-step-equations/v/why-we-do-the-same-thing-to-both-sides-two-step-equations
you need to know how to solve such equations, they show up everywhere...
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