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It's number 2.
so you will get it by plugging n = 1 , 2 ... for example, the first is t1 = 5 * 2^0 = 5 can you do the rest ?
You confused me even more lmaoo
sorry, you have t(n) = 5 * 2^(n-1) the first will be t(1) so you plug n = 1. t(1) = 5 * 2^(1-1) = 5 * 1 = 5 the second will be t(2) so you plug n =2 etc
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