can i get some quick help with 3 geometry questions??
@amistre64
what are the questions?
okay here is the first one,
i dont have a picture of the triangle, how do you want me to explain that?
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B and C, as shown below: A source of laser light is at point A on the ground between two parallel walls. The walls are perpendicular to the ground. AB is a ray of light which strikes the wall on the left at point B. The length of AB is 40m. AC is a ray of light which strikes the wall on the right at point C which is 80 m above the ground. The ray AB makes an angle of 60 degrees with the ground. The ray AC makes an angle of 45 degrees with the ground. What is the distance between the walls? 80 m 180 m 90 m 100 m
use the draw function and draw it
thats not the right question lol
dont pay attention to that haha
ok haha
what is the value of sin x ? |dw:1413835628807:dw|
like i know pretty much what i am doing, just i dont have a brain for math lol. so im a a little slower getting started on questions :/
you want to pick sin, cos, or tan and use the sides to find x, so for examples you could use sin(x)=12/13 which then equals 67.38
okay so
im trying to comprehend this lol
do you understand how to use sin, cos, and tan?
so you would use sin?
yes i do, somewhat lol
sin = opposite over hypotenuse
Yes that is correct! that numbers would you plug in for sin?
*what numbers, not that number
13 is my hopotenuse. 13 is my opposite?
i mean 12
Yup! Good job
then heres my problem , i forget what to do next :(
ok, so....\[\sin x=\frac{ opposite }{ hypotenuse }\]\[\sin x=\frac{ 12 }{ 13}\]\[x=\sin^{-1} \frac{ 12 }{ 13 }\] x=67.38
so you divided?
anything else?
yeah i have two more questions, but just to be clear. i think im confusing myself.
what did you do with 12/13 to get that answer
you need to take the inverse of sin on both sides to get x alone, so you would do Sin^-1(12/13)
im going to open up the next question so i can medal you again
@GWiz
ok
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