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Mathematics 9 Online
OpenStudy (anonymous):

What is the solution to the system of equations? @ganeshie8

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

subtract both the equations vertically

OpenStudy (anonymous):

What do I subtract from them?

ganeshie8 (ganeshie8):

x + y = 5 x - 2y = 2 ------------- 0 + 3y = 3 y = ?

OpenStudy (anonymous):

How did you get 3y? I see how you get it if you add but how do you get it if you subtract?

ganeshie8 (ganeshie8):

x + ` y` = 5 x - `2y` = 2 ------------- 0 + `3y` = 3

ganeshie8 (ganeshie8):

`y` - - `2y`

OpenStudy (anonymous):

Wouldn't you have to add to get 3y?

ganeshie8 (ganeshie8):

adding them both gives you `-y` however its not useful because the x term wont disappear

ganeshie8 (ganeshie8):

we're subtracting because we want to kill x term so that we can solve y first

ganeshie8 (ganeshie8):

note that x-x = 0

OpenStudy (anonymous):

I get it! So it would be like 2 negatives=a positive?

ganeshie8 (ganeshie8):

Exactly !

OpenStudy (anonymous):

Ok! So now what do you have?

OpenStudy (anonymous):

3y=3 ------- y=1??

ganeshie8 (ganeshie8):

Yup!

ganeshie8 (ganeshie8):

plug that y value in any of the given equations and solve x

OpenStudy (anonymous):

Ok, so what next? Now that we have ?, 1

OpenStudy (anonymous):

x+1 = 5 so x = 4??

ganeshie8 (ganeshie8):

Perfect !

OpenStudy (anonymous):

Yeah! So the answer would be 4,1?

ganeshie8 (ganeshie8):

\(\large \color{Red}{\checkmark}\)

OpenStudy (anonymous):

Ok, I will close this question and open another for my 2nd question. And tag you :)

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