Find a rectangular equation for the plane curve defined by the parametric equations. x = t - 3, y = t2 + 5

Question

anonymous · Answer

the first step I have is y - 5 = t2, but I'm not sure if this is correct or what follows

aum · Answer

Eliminate the parameter t.
x = t - 3
t = x + 3
put this in y and you will have y as a function of x.

anonymous · Answer

y= 2(x+3) +5 is the next part?

aum · Answer

$$
y = (x+3)^2 + 5
$$

anonymous · Answer

oh my apologies, it's because the variable is in front of the number it's an exponent, I thought it was tx2 instead of t^2. Okay. 

y = x^2+6x + 9 + 5

y= x^2 + 6x + 14 ?

aum · Answer

Yes.

anonymous · Answer

thanks so much for the help! for future reference, if the variable is in front of the number is it always an exponent? I'm just used to it being marked with an ^.