Question

Express y in terms of x
Quite hard for me...

Answer 1

So I currently have from a differiential equation:
\[\frac{ y-1 }{ y+1 }=\frac{ x^2 }{ 4 }\]
and have to express it as y = ?

I have tried cross multiplying the fractions and simplifying but I have no idea at all

Answer 2

\[
\frac{ y-1 }{ y+1 }=\frac{ x^2 }{ 4 } \\
4y - 4 = x^2y + x^2 \\
4y - x^2y = x^2 + 4 \\
y(4 - x^2) = x^2 + 4 \\
y = \frac{4+x^2}{4-x^2} \\
\]

Answer 3

Ah thank you. I just got stuck on factorising it on the second to last line!