A Math Riddle: (PLEASE HELP)
One number is 6 less than a second number. Twice the second number is 42 more than 5 times the first. Find the two numbers.

Question

A Math Riddle: (PLEASE HELP) 
One number is 6 less than a second number. Twice the second number is 42 more than 5 times the first. Find the two numbers.

anonymous · Answer

THANKS FOR PARTICIPATING IN THE 1ST MEDAL QUESTION

anonymous · Answer

I HAVE ONE PUT UP SO CHECK IT OUT BEFORE SOMEONE GETS THERE

melissa_something · Answer

Oh damn

anonymous · Answer

oh wow no one helps you

melissa_something · Answer

I knowwwww it's aggravating @KayleeNeedsHelp

anonymous · Answer

that has happened to a lot of people don't worry. I would help if I could

anonymous · Answer

can we do a medal exchange

melissa_something · Answer

Okay

anonymous · Answer

i gave you a medal now you give me one

mathmath333 · Answer

$\large\tt \begin{align} \color{black}{\text{let first number be x-6}\~\
\text{thus the second number would be x}\~\
2x=42+5(x-6) }\end{align}$

melissa_something · Answer

Youre amazing @mathmath333

melissa_something · Answer

So, distribute the 5 so it will be 2x=42+5x-30

melissa_something · Answer

Combine like terms? @mathmath333

anonymous · Answer

see, you found your help, never worry!

mathmath333 · Answer

x should come -4 here