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Physics 22 Online
OpenStudy (anonymous):

Object of mass 80kg is dropped from plane. Terminal velocity is 60m/s. what is velocity after 2 seconds. the way i thought about it would be V = Vi +at so V = 0 + (9.8*1) for the first second and V = 0 + (9.8 *2) for the second second which would be 19.6 because the object has not yet reached terminal velocity, but 19.6 is not one of the correct answers to choose from

OpenStudy (amistre64):

what are the options?

OpenStudy (amistre64):

velocity is a vector, so direction is important as well .... so a negative value may be technically appropriate

OpenStudy (anonymous):

well i changed the numbers because i didnt want to straight copy the book i thought understanding how it was solved would be better. But in my book the mass is 60kg and Terminal velocity is 55m/s. options are 110m/s 16.5m/s 34m/s 20m/s

OpenStudy (amistre64):

your thoughts were accurate with the information you provided v = gt

OpenStudy (anonymous):

so i guess just round to 20m/s

OpenStudy (amistre64):

yep

OpenStudy (anonymous):

alright it just seemed weird to me that one option was a decimal while the others were not. and since i got a decimal i just thought i was doing something wrong

OpenStudy (amistre64):

:) some times they assume g = 10 m/s^2

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