Question

Help please :)


What is the equation of the line that passes through the points (-3, 2) and (-5, 8)?

3x - y = -11

3x + y = - 7

3x + y = 5

x + 3y = 3

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -3}}\quad ,&{\color{blue}{ 2}})\quad &({\color{red}{ -5}}\quad ,&{\color{blue}{ 8}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 2

well... you don't really have to solve for "y"
just simply set in "standard" form... that is.... move the "x" and "y" to the left-side

Answer 3

hi again :D what i got before is y= -3 x -7 ? why is that

Answer 4

that is correct... and if you move the "x" over to the left side, that'd be
\(\bf \large 3x+y=-7\)

Answer 5

So B! once again thank you for your help!

Answer 6

yw