Question

what is the equation in slope-intercept form for the line that passes through points (-1,3) and (-2,-3)?

Answer 1

find slope

Answer 2

y=mx+b is the formula for slope intercept form

Answer 3

(y2-y1)/(x2-x1)

Answer 4

m is slope, ^^ using that you get -6

Answer 5

(-3-3)/(-2--1)=-6/-1=6

Answer 6

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -1}}\quad ,&{\color{blue}{ 3}})\quad &({\color{red}{ -2}}\quad ,&{\color{blue}{ -3}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 7

my bad 6 lol

Answer 8

y=6(x)+b
3=6(-1)+b
3=-6+b
9=b

Answer 9

y=6x+9

Answer 10

now plug in one of the coordinate sets to check

Answer 11

Qué entiende mi bebé?

Answer 12

@jim_thompson5910

Answer 13

help me please