Question

10x^2+9=x

Answer 1

@jim_thompson5910

Answer 2

were you able to get started?

Answer 3

no

Answer 4

the first step is to get 10x^2+9=x into standard form

Answer 5

so we have to get it into ax^2 + bx + c = 0 form

Answer 6

we do so by subtracting x from both sides.

10x^2+9=x

10x^2+9-x=x-x

10x^2 - x + 9 = 0

Answer 7

10x^2 - x + 9 = 0 is really 10x^2 + (-1)x + 9 = 0

it is in the form ax^2 + bx + c = 0

where

a = 10
b = -1
c = 9

now use the quadratic formula to solve

Answer 8

what do you get?

Answer 9

theres no solution

Answer 10

what did you get for the discriminant?

Answer 11

discriminant?

Answer 12

yes D = b^2 - 4ac

Answer 13

basically the stuff under the square root

Answer 14

(-1)^2-4*10*9

Answer 15

good, D = -359

that is negative which means that there are no real solutions