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how to solve an equation in quadratic form 3d^2/3-d^1/3-4=0 MEDAL AND FAN WILL BE GIVEN
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@dan815 hey can you help
i know how to start it js
the simpler way would be to simply multiply both left and right sides by 3 thus getting rid of the denominators
do you know the method when you replace the common with u ?
like 3(d^1/3)^2- d(1/3)-4=0 let (d^1/3) = u
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and then it would be 3u^2-u-4=0
hmm
is there a sum and product for -1 and -12
3-4 = -1 3* -4 = -12
thank you!!!! @jdoe0001
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yw
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