6x+8y=6
x-32y=-99
Solve using elimination, Plese Help
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OpenStudy (anonymous):
multiply the first equation by \(4\) and start with
\[24x+32y=24\\
x-32y=-99\] then add them up
OpenStudy (anonymous):
Why 4?
OpenStudy (anonymous):
add them up and you will see why 4
OpenStudy (anonymous):
Ok I asked so I know how to start other problems. how do you know what number to multiply by
OpenStudy (anonymous):
do you see that when you add the \(y\) terms go away? that was the point
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
\[24x+32y=24\\
x-32y=-99\] adding gives
\[25x=-75\] no y's so you can solve for \(x\) alone
OpenStudy (anonymous):
multiplying by 4 is what made that work
you have to figure that part out on your ownb
what number would you multiply by to make one variable go away when you add
OpenStudy (anonymous):
sometimes you have to multiply both equations by some number
not in this case because 32 is a multiple of 8
OpenStudy (anonymous):
oohh ok. so i got -3x and to solve for y I do the same?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
first off i assume you mean \(x=-3\) right?
OpenStudy (anonymous):
Right
OpenStudy (anonymous):
then since you know what x is , you do not have to redo the procedure
replace x by -3 in either equation and solve for y
OpenStudy (anonymous):
\[x-32y=-99\\
-3-32x=-99\] etc
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