How do you convert y-5=-2(x+1)^2 to standard and intercept modes?
Well, add 5 and that's usually Vertex Form. Then, multiply out and simplify the right side for Standard Form.
Yeah, but the factoring is what is so tricky
Factoring? There is no need to factor. It is already in a factored form. Do you need to find zeros?
yes, the form it currently holds is vertex. To get to intercept form, You must factor from standard
Factor or solve. Put it in Standard Form and see how easy it is.
I did put it into standard form, and I got y= -2x^2-4x+3 remember the y-5 on the other side
y-5=-2(x+1)^2 y-5 = -2(x^2 + 2x + 1) y-5 = -2x^2 - 4x - 2 y = -2x^2 - 4x +3 Do you know the Discriminant? It will tell you that this cannot be factored. Just use the Quadratic Formula.
So how am I supposed to answer the question for putting it in standard form? Also, I need to graph it and I'm just getting confused with what they expect here
My own idiocy surprises me sometimes, it is able to be graphed.
Thanks so much
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