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Mathematics 6 Online
OpenStudy (anonymous):

What is the equation of the graphed line? Hint: Determinehttp://assets.openstudy.com/updates/attachments/5445ef27e4b02731fd676c4c-igivemedalsandfollow%2521-1413869368788-ms_imc1405161000015.jpg the slope of the line.

OpenStudy (anonymous):

@mayankdevnani

OpenStudy (mayankdevnani):

@igivemedalsandfollow! can you identify (0,0) , (-1,5) and (1,-5) these points in your graph ?

OpenStudy (anonymous):

yes

OpenStudy (mayankdevnani):

good

OpenStudy (mayankdevnani):

then,we have a formula for finding the slope of a line :- \[\large \bf Slope=\frac{y_2-y_1}{x_2-x_1}\] where, (x1,y1) and (x2,y2) are points on a straight line.

OpenStudy (mayankdevnani):

lets consider two points be :- (0,0) and (-1,5)

OpenStudy (mayankdevnani):

understood?

OpenStudy (anonymous):

yes

OpenStudy (mayankdevnani):

good :)

OpenStudy (mayankdevnani):

now plug the points in the given formula :- \[\large \bf Slope=\frac{5-0}{-1-0}=\frac{5}{-1}=-5=\large \bf \color{red}{Answer}\]

OpenStudy (anonymous):

so its -5

OpenStudy (mayankdevnani):

and we denote SLOPE of a line by `m`

OpenStudy (mayankdevnani):

yeah. @igivemedalsandfollow!

OpenStudy (anonymous):

do I wrtite -5m??

OpenStudy (mayankdevnani):

no, m=-5

OpenStudy (mayankdevnani):

we denote SLOPE=m

OpenStudy (mayankdevnani):

hope you understand. @igivemedalsandfollow!

OpenStudy (anonymous):

can you help me with some more???

OpenStudy (mayankdevnani):

yeah,why not ?

OpenStudy (mayankdevnani):

post it !!

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