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@sephiroth_07
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so we nee\[-8\le2x-4<2\]d to get x by itself
add -4 to both sides?
I dont know :(
you have to separate the inequality into 2 separate ones so \[-8\le2x-4\] and \[2x-4<2\] the you solve for each the same way we did on the lastone
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\[-8\le2x-4\] \[4+-8\le2x\] \[-4\le2x\] \[\frac{ -4 }{ 2 }=x\] \[-2lex\]
that is the first part \[-2\le X\] can you do the second part?
x is less than or equal to 3
is less than, the second part does not have the = part see? \[x <3\]
I mean is less than sorry
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yeah
yeah so now we put them together and we get \[-2\le x <3\]
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