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Mathematics 17 Online
OpenStudy (anonymous):

@sephiroth_07

OpenStudy (anonymous):

OpenStudy (anonymous):

so we nee\[-8\le2x-4<2\]d to get x by itself

OpenStudy (anonymous):

add -4 to both sides?

OpenStudy (anonymous):

I dont know :(

OpenStudy (anonymous):

you have to separate the inequality into 2 separate ones so \[-8\le2x-4\] and \[2x-4<2\] the you solve for each the same way we did on the lastone

OpenStudy (anonymous):

\[-8\le2x-4\] \[4+-8\le2x\] \[-4\le2x\] \[\frac{ -4 }{ 2 }=x\] \[-2lex\]

OpenStudy (anonymous):

that is the first part \[-2\le X\] can you do the second part?

OpenStudy (anonymous):

x is less than or equal to 3

OpenStudy (anonymous):

is less than, the second part does not have the = part see? \[x <3\]

OpenStudy (anonymous):

I mean is less than sorry

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

yeah so now we put them together and we get \[-2\le x <3\]

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