Question

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6)

y = 1 over 3x + 3
y = -3x + 3
y = 1 over 3x + 3
y = -3x + 7

Answer 1

first find the slope in the equation y = -3x + 12. In y = mx + b form, the slope is in the m position...so the slope of this equation is -3. A parallel line will have the same slope.

Now we use y = mx + b
slope(m) = -3
(-1,6)...x = -1 and y = 6
now sub into y = mx + b and since we know the slope(m) is -3, we need to find the y intercept (b)...so we solve for b
y = mx + b
6 = -3(-1) + b
6 = 3 + b
6 - 3 = b
3 = b

so your parallel equation is : y = -3x + 3