Simplify the expression -

{ (2x^2y)^3 / (3xy^3)^2 } ^2

A - 16x^6/81y^4
B - 8x^4/9y^3
C - 16x^4/81y^8
D - 64x^8/81y^6

Question

Simplify the expression - 

{ (2x^2y)^3 / (3xy^3)^2 } ^2

A - 	16x^6/81y^4
B - 8x^4/9y^3
C - 16x^4/81y^8
D - 64x^8/81y^6

fibonaccichick666 · Answer

any ideas on  how to begin?

anonymous · Answer

@FibonacciChick666 I have no idea how to start or anything?

fibonaccichick666 · Answer

ok, so, let's make sure I have this right to begin. This is the problem?
\[(\frac{ (2x^2y)^3 }{ (3xy^3)^2 }) ^2

fibonaccichick666 · Answer

oops, $$(\frac{ (2x^2y)^3 }{ (3xy^3)^2 }) ^2$$

anonymous · Answer

yes thats right @FibonacciChick666

fibonaccichick666 · Answer

ok, so what rules for exponents do you know?

anonymous · Answer

umm well i think u would start by distributing the 3 to both 2s on the top and distribute the 2 to both 3s on the bottom? right @FibonacciChick666

fibonaccichick666 · Answer

anonymous · Answer

i just guessed B and idk if i got it right or wrong

fibonaccichick666 · Answer

no guessing!  it is not allowed, please, did you read the website?