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Mathematics 23 Online
OpenStudy (jordanloveangel):

How many solutions does the equation have? http://static.k12.com/bank_packages/files/media/mathml_d13621783644288c1c60b0eaa58106ba953e5d97_1.gif A. one solution B. infinite solutions C. no solution

geerky42 (geerky42):

Start by distributing

geerky42 (geerky42):

\(2(2x+5) = 4(x+3)\\~\\4x+20 = 4x+12\) Do you know what to do next?

OpenStudy (jordanloveangel):

u add 12 & 20

OpenStudy (jordanloveangel):

@geerky42

OpenStudy (jordanloveangel):

@sammie2017

geerky42 (geerky42):

How about subtract both sides by 4x?

OpenStudy (jordanloveangel):

that might work

geerky42 (geerky42):

yeah, what do you get after doing that?

OpenStudy (jordanloveangel):

20-4=16 & 12-4=8 right?

geerky42 (geerky42):

4x, not just 4

OpenStudy (jordanloveangel):

-20 = -12

OpenStudy (jordanloveangel):

@geerky42 @Teddyiswatshecallsme

OpenStudy (jordanloveangel):

@Ell

OpenStudy (jordanloveangel):

@jane11509

OpenStudy (jordanloveangel):

ill fan and mdal

geerky42 (geerky42):

well, you are supposed to have \(20 = 12\) Since this equation is false (20 is not equal to 12, right?) that means there is no solution. Does that make sense?

OpenStudy (jordanloveangel):

yeah

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