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How many solutions does the equation have? http://static.k12.com/bank_packages/files/media/mathml_d13621783644288c1c60b0eaa58106ba953e5d97_1.gif A. one solution B. infinite solutions C. no solution
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Start by distributing
\(2(2x+5) = 4(x+3)\\~\\4x+20 = 4x+12\) Do you know what to do next?
u add 12 & 20
@geerky42
@sammie2017
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How about subtract both sides by 4x?
that might work
yeah, what do you get after doing that?
20-4=16 & 12-4=8 right?
4x, not just 4
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-20 = -12
@geerky42 @Teddyiswatshecallsme
@Ell
@jane11509
ill fan and mdal
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well, you are supposed to have \(20 = 12\) Since this equation is false (20 is not equal to 12, right?) that means there is no solution. Does that make sense?
yeah
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