A box contains 27 parts, of which 5 are defective and 22 are nondefective. 2 parts are selected without replacement.
I need help finding the probability that one is defective, both are defective, and neither are defective. HELP!!!

Question

A box contains 27 parts, of which 5 are defective and 22 are nondefective. 2 parts are selected without replacement.
I need help finding the probability that one is defective, both are defective, and neither are defective. HELP!!!

ccswims · Answer

there is an 81% chance of you picking a non defective one and a 19% chance you will choose a defective one

ccswims · Answer

there is a less likely chance of you ever getting a defective one

ccswims · Answer

for every 4.4 non defective there is 1 defective one. So neither

anonymous · Answer

i need it in decimal form, it is saying these answers aren't correct. im not sure how to figure this out

kropot72 · Answer

$$\large P(1\ defective)=\frac{C(5,1) \times C(22, 1)}{C(27, 2)}=you\ can\ calculate$$