(will fan and medal whoever answers in the next five minutes)
Determine which polynomial has (x + 4) as a factor.
A. x^2+11x+28
B. x^2-6x+8
C. x^2+7x+12
D. x^2-4x+16
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OpenStudy (sydthekid913):
@zepdrix @jim_thompson5910
OpenStudy (sydthekid913):
@leonardo0430
OpenStudy (sydthekid913):
@sleepyjess
OpenStudy (sleepyjess):
do you know how to factor polynomials?
OpenStudy (sydthekid913):
yes
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OpenStudy (sydthekid913):
btw I like ur owl xD
OpenStudy (sleepyjess):
tank you :-)
OpenStudy (sleepyjess):
ok so you know that they have to multiply to be the 3rd number and add to be the second number correct?
OpenStudy (sydthekid913):
yes
OpenStudy (sleepyjess):
ok so lets start with the first one
what are the factors of 28?
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OpenStudy (sydthekid913):
1,2,4,7,14,28
OpenStudy (sleepyjess):
ok so do any of those add to be 11?
OpenStudy (sleepyjess):
and for this one both factors are either both positive or both negative
OpenStudy (sydthekid913):
I don't know but I'm running out of time!
OpenStudy (sleepyjess):
4 and 7 add to be 11 correct?
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OpenStudy (sydthekid913):
yes
OpenStudy (sleepyjess):
ok so now lets do (x+4)(x+7)
\(x^2+4x+7x+28\)
simplifiy that
\(x^2+11x+28\)
OpenStudy (sydthekid913):
so it's not a
OpenStudy (sleepyjess):
yes it is A
notice how the factors are (x+4) and (x+7)
OpenStudy (sydthekid913):
but A is x^2-11x-28 you got addition
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OpenStudy (sleepyjess):
This is what my screen says
(will fan and medal whoever answers in the next five minutes)
Determine which polynomial has (x + 4) as a factor.
A. x^2+11x+28
B. x^2-6x+8
C. x^2+7x+12
D. x^2-4x+16
OpenStudy (sydthekid913):
o I must have typed it in wrong
OpenStudy (sleepyjess):
ok then factors of 8
1, 2, 4, 8
both must be negative since 8 is positive but 6 is negative
OpenStudy (sleepyjess):
-4, -2
OpenStudy (sydthekid913):
I think it's C.
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OpenStudy (sleepyjess):
we know just from those factors it cant be B
OpenStudy (sydthekid913):
yes
OpenStudy (sleepyjess):
factors of 12
1, 2, 3, 4, 6, 12
both positive must be positive since both number are positive
3 and 4
OpenStudy (sleepyjess):
(x+3)(x+4)
\(x^2+3x+4x+12=x^2+7x+12\)
OpenStudy (sydthekid913):
Ok so I was right?
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OpenStudy (sleepyjess):
yes
OpenStudy (sydthekid913):
cool!
OpenStudy (sydthekid913):
thank you!
OpenStudy (sydthekid913):
YAY I GOT 100 PERCENT WOOHOO!!!
OpenStudy (sleepyjess):
do you have any more questions? if so im sorry but i cant help i am in the middle of a history test right now and i cant let it time me out or it will submit it with the answers i have and im not done yet
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OpenStudy (sydthekid913):
O ok ya that is what mine just did to me :P but I still got 100 YAY