Question

Nuclear physics

Answer 1

@Kainui

Answer 2

For this calculation, assume that the gold atom is fixed and the collision is head-on.

Answer 3

@UnkleRhaukus

Answer 4

Draw out a picture and label as much as you can and I'll help you out. =D

Answer 5

Bohr radius is \[a_0 = \in_0 \frac{ h^2 }{ \pi m e^2 }\]

So for the proton, I'd draw it outside right, heading towards the nucleus of the gold atom.

Answer 6

I'm not exactly sure of the formula for the coulomb barrier, is that the regular f = kq1q2/r