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Algebra
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10x^2+7x-3
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how do you factorise this?
do u need a solution or u need to know to make factors?
\[10x^2+7x-3\] Firstly, multiply 10 and -3. That gets you -30. Then, think to yourself; which numbers add up to 7 but multiply to make -30? If it helps, write all the multiples of -30 out, eg: 30 x -1 15 x -2 10 x -3 6 x -5 So, which one of these adds up to make 7? That would be 10 and -3. So: \[10x^2+10x-3x-3\] Then, you "make" brackets.\[10x(x +1)-3(x+1)\] From this, you can get:\[(10x-3)(x+1)\] which is the beginning equation factorised. If you still don't understand, I can go through it again with you, step by step and with more detail :) just message me or reply, and I'll be there!
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