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Mathematics 9 Online
OpenStudy (anonymous):

The temperature at noon was –6.5⁰C. The temperature rose 3.5⁰C from noon to 1 p.m. The temperature decreased t degrees centigrade from 1 p.m. to 2 p.m. The temperature at 2 p.m. was –12⁰C. Which equation can be used to solve for t? A. –6.5 – 3.5 – t = –12 B. –6.5 + 3.5 + t = –12 C. –6.5 + 3.5 – t = –12 D. –6.5 – 3.5 + t = –12

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

i think it is b

OpenStudy (anonymous):

@keana11

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@Here_to_Help15

OpenStudy (anonymous):

b

OpenStudy (cwrw238):

starts at -6.5 then you add 3.5 and then subtract t

OpenStudy (cwrw238):

not b

OpenStudy (anonymous):

c

OpenStudy (igreen):

We start at -6.5, it raises by 3.5 so that's: -6.5 + 3.5 Then it decreases by t: -6.5 + 3.5 - t The result is -12: -6.5 + 3.5 - t = 12

OpenStudy (igreen):

You got it. @newwar248

OpenStudy (cwrw238):

yep its c

OpenStudy (anonymous):

thanks

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